Answer
$21+20i$
Work Step by Step
$(5+2i)(5+2i)$
$=5(5+2i)+2i(5+2i)$
$=25+10i+10i+4i^{2}$
$=25+20i+4(-1)$
$=25+20i-4$
$=21+20i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 50
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