Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises: 52

Answer

$29$

Work Step by Step

$(2+5i)(2-5i)$ =$2(2-5i)+5i(2-5i)$ =$4-10i+10i-25i^{2}$ =$4-10i+10i-25(-1)$ =$4-25(-1)$ =$4+25$ =$29$
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