Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 62

Answer

$\frac{41}{29}-\frac{1}{29} i$

Work Step by Step

Given \begin{equation} \frac{3+7 i}{2+5 i}. \end{equation} Multiply both numerator and denominator by the conjugate of the denominator and simplify. \begin{equation} \begin{aligned} \frac{3+7 i}{2+5 i}&=\frac{3+7 i}{2+5 i}\cdot \frac{(2-5 i)}{(2-5 i)}\\ & =\frac{3(2-5 i)+7i(2-5 i)}{4+25}\\ &=\frac{6-15 i+14i+35}{29}\\ &= \frac{41}{29}-\frac{1}{29} i. \end{aligned} \end{equation} We got $$\frac{3+7 i}{2+5 i}=\frac{41}{29}-\frac{1}{29} i.$$
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