Answer
$-14-22i$
Work Step by Step
$(2-4i)(3-5i)$
$=2(3-5i)-4i(3-5i)$
$=6-10i-12i+20i^{2}$
$=6-22i+20(-1)$
$=6-22i-20$
$=-14-22i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 45
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
