Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises: 45

Answer

$-14-22i$

Work Step by Step

$(2-4i)(3-5i)$ $=2(3-5i)-4i(3-5i)$ $=6-10i-12i+20i^{2}$ $=6-22i+20(-1)$ $=6-22i-20$ $=-14-22i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.