Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 60

Answer

$\frac{83}{24}-\frac{35}{24} i \approx 3.458-1.458 i$

Work Step by Step

Given \begin{equation} \frac{3.5+8.3 i}{2.4 i}. \end{equation} Multiply both numerator and denominator by $i$. \begin{equation} \begin{aligned} \frac{3.5+8.3 i}{2.4 i}&=\frac{3.5+8.3 i}{2.4 i}\cdot \frac{i}{i}\\ &=\frac{3.5i+8.3 i^2}{2.4 i^2}\\ &=\frac{3.5i-8.3 }{-2.4 }\\ &= \frac{83}{24}-\frac{35}{24} i \\ &\approx 3.458-1.458 i. \end{aligned} \end{equation} The solution is $$\frac{83}{24}-\frac{35}{24} i \approx 3.458-1.458 i.$$
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