Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 58



Work Step by Step

$\frac{5+8i}{3i}$ =$\frac{5+8i}{3i}\times\frac{3i}{3i}$ =$\frac{3i(5+8i)}{3i\times3i}$ =$\frac{15i+24i^{2}}{9i^{2}}$ =$\frac{15i+24(-1)}{9(-1)}$ =$\frac{-24+15i}{-9}$ =$\frac{-8+5i}{-3}$ =$\frac{8-5i}{3}$ =$\frac{8}{3}-\frac{5}{3}i$
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