Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 57

Answer

$\frac{7}{2}-\frac{4i}{2}$

Work Step by Step

$\frac{4+7i}{2i}$ =$\frac{4+7i}{2i}\times\frac{2i}{2i}$ =$\frac{2i(4+7i)}{2i\times2i}$ =$\frac{8i+14i^{2}}{4i^{2}}$ =$\frac{8i+14(-1)}{4(-1)}$ =$\frac{-14+8i}{-4}$ =$\frac{-7+4i}{-2}$ =$\frac{7-4i}{2}$ =$\frac{7}{2}-\frac{4i}{2}$
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