Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 80



Work Step by Step

We are given that $f(x)=\sqrt (2x+3)$. Therefore, $f(-1)=\sqrt (2(-1)+3)=\sqrt (-2+3)=\sqrt 1=1$ We know this, because $1^{2}=1\times1=1$
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