Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 41

Answer

$4x^{2}$

Work Step by Step

$\sqrt[4] (256x^{8})=4x^{2}$, because $(4x^{2})^{4}=4x^{2}\times4x^{2}\times4x^{2}\times4x^{2}=(4\times4\times4\times4)\times x^{2+2+2+2}=256x^{8}$
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