Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 69

Answer

$\frac{5}{7}$

Work Step by Step

$\sqrt (\frac{25}{49})=\frac{5}{7}$, because $(\frac{5}{7})^{2}=\frac{5}{7}\times\frac{5}{7}=\frac{25}{49}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.