Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 29



Work Step by Step

$\sqrt[4] 16=2$, because $2^{4}=2\times2\times2\times2=16$ Therefore, $-\sqrt[4] 16=-2$, as we are taking the opposite of $\sqrt[4] 16$
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