Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 78



Work Step by Step

We are given that $g(x)=\sqrt[3] (x-8)$. Therefore, $g(0)=\sqrt[3] (0-8)=\sqrt[3] (-8)=-2$ We know this, because $(-2)^{3}=-2\times-2\times-2=-8$
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