Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 35



Work Step by Step

$\sqrt[5] (x^{20})=x^{4}$, because $(x^{4})^{5}=x^{4}\times x^{4}\times x^{4}\times x^{4}\times x^{4}=x^{4+4+4+4+4}=x^{20}$
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