Answer
$x^{4}$
Work Step by Step
$\sqrt[5] (x^{20})=x^{4}$, because $(x^{4})^{5}=x^{4}\times x^{4}\times x^{4}\times x^{4}\times x^{4}=x^{4+4+4+4+4}=x^{20}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 35
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