Answer
$-2a^{7}b^{2}$
Work Step by Step
$\sqrt[3] (-8a^{21}b^{6})=-2a^{7}b^{2}$, because
$(-2a^{7}b^{2})^{3}=-2a^{7}b^{2}\times -2a^{7}b^{2}\times -2a^{7}b^{2}=(-2\times-2\times-2)\times a^{7+7+7}\times b^{2+2+2}=-8a^{21}b^{6}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 64
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