Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 39

Answer

$9x^{2}

Work Step by Step

$\sqrt (81x^{4}=9x^{2}$, because $(9x^{2})^{2}=9x^{2}\times9x^{2}=(9\times9)\times(x^{2+2})=81x^{4}$
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