Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 76



Work Step by Step

$\sqrt[4] (\frac{y^{4}}{81x^{4}})=\frac{y}{3x}$, because $(\frac{y}{3x})^{4}=\frac{y}{3x}\times\frac{y}{3x}\times \frac{y}{3x}\times \frac{y}{3x}=\frac{y^{1+1+1+1}}{(3\times3\times3\times3)\times x^{1+1+1+1}}=\frac{y^{4}}{81x^{4}}$
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