Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 65



Work Step by Step

$\sqrt[4] (a^{16}b^{4})=a^{4}b$, because $(a^{4}b)^{4}=a^{4}b\times a^{4}b\times a^{4}b\times a^{4}b=a^{4+4+4+4}\times b^{1+1+1+1}=a^{16}b^{4}$
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