Answer
$|x-4|$
Work Step by Step
We are told that $\sqrt[n] a^{n}=|a|$ when n is an even positive integer.
In this case, we must factor in order to find $a$.
$x^{2}-8x+16=(x-4)(x-4)=(x-4)^{2}$
Therefore, $a=(x-4)$.
$\sqrt (x-4)^{2}=|x-4|$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 54
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