Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 54



Work Step by Step

We are told that $\sqrt[n] a^{n}=|a|$ when n is an even positive integer. In this case, we must factor in order to find $a$. $x^{2}-8x+16=(x-4)(x-4)=(x-4)^{2}$ Therefore, $a=(x-4)$. $\sqrt (x-4)^{2}=|x-4|$
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