Answer
$x^{2}y^{3}$
Work Step by Step
$\sqrt[4] (x^{8}y^{12})=x^{2}y^{3}$, because
$(x^{2}y^{3})^{4}=x^{2}y^{3}\times x^{2}y^{3}\times x^{2}y^{3}\times x^{2}y^{3}=x^{2+2+2+2}\times y^{3+3+3+3}=x^{8}y^{12}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 66
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