Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 75



Work Step by Step

$\sqrt[4] (\frac{x^{4}}{16})=\frac{x}{2}$, because $(\frac{x}{2})^{4}=\frac{x}{2}\times\frac{x}{2}\times \frac{x}{2}\times \frac{x}{2}=\frac{x^{1+1+1+1}}{2\times2\times2\times2}=\frac{x^{4}}{16}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.