Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 70



Work Step by Step

$\sqrt (\frac{4}{81})=\frac{2}{9}$, because $(\frac{2}{9})^{2}=\frac{2}{9}\times\frac{2}{9}=\frac{4}{81}$
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