Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 42



Work Step by Step

$\sqrt (256x^{8})=16x^{4}$, because $(16x^{4})^{2}=16x^{4}\times16x^{4}=(16\times16)\times x^{4+4}=256x^{8}$
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