Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 63



Work Step by Step

$\sqrt[3] (-27x^{12}y^{9})=-3x^{4}y^{3}$, because $(-3x^{4}y^{3})^{3}=-3x^{4}y^{3}\times -3x^{4}y^{3}\times -3x^{4}y^{3}=(-3\times-3\times-3)\times x^{4+4+4}\times y^{3+3+3}=-27x^{12}y^{9}$
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