Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 9



Work Step by Step

Using the rules of factoring trinomials, we obtain: $x^{2}-5x-14=0$ $x^{2}+2x-7x-14=0$ $x(x+2)-7(x+2)=0$ $(x+2)(x-7)=0$ $(x+2)=0$ and $(x-7)=0$ $x=-2$ and $x=7$ Therefore, the solution set is {$-2,7$}.
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