Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 14



Work Step by Step

Using the rules of factoring trinomials and setting the factors equal to zero, we obtain: $4y^{2}-21y-18=0$ $4y^{2}+3y-24y-18=0$ $y(4y+3)-6(4y+3)=0$ $(4y+3)(y-6)=0$ $(4y+3)=0$ and $(y-6)=0$ $y=-\frac{3}{4}$ and $y=6$ Therefore, the solution set is {$-\frac{3}{4},6$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.