Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 11



Work Step by Step

Using the rules of factoring trinomials, we obtain: $n^{2}+5n-6=0$ $n^{2}-1n+6n-6=0$ $n(n-1)+6(n-1)=0$ $(n-1)(n+6)=0$ $(n-1)=0$ and $(n+6)=0$ $n=1$ and $n=-6$ Therefore, the solution set is {$-6,1$}.
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