Answer
No real solution.
Work Step by Step
We apply the quadratic formula:
$ x = \frac{ -b \pm \sqrt{b^2 -4ac}}{2a}$
$ x = \frac{ -0 \pm \sqrt{0^2 -4(1)(25)}}{2}$
$ x = \frac{ \sqrt{-100}}{2}$
Since you cannot take the square root of a negative number, there is no real solution.
