## Elementary Algebra

We apply the quadratic formula: $x = \frac{ -b \pm \sqrt{b^2 -4ac}}{2a}$ $x = \frac{ -0 \pm \sqrt{0^2 -4(1)(25)}}{2}$ $x = \frac{ \sqrt{-100}}{2}$ Since you cannot take the square root of a negative number, there is no real solution.