Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 29

Answer

{$-4\sqrt 2,4\sqrt 2$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $y^{2}=32$ Step 2: $y=\pm \sqrt {32}$ Step 3: $y=\pm \sqrt {16\times 2}$ Step 4: $y=\pm (\sqrt {16}\times \sqrt 2)$ Step 5: $y=\pm (4\times \sqrt 2)$ Step 6: $y=\pm 4\sqrt 2$ The solution set is {$-4\sqrt 2,4\sqrt 2$}.
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