Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 52

Answer

No real number solutions

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(2x+9)^{2}=-6$ Step 2: $2x+9=\pm \sqrt {-6}$ Since $\sqrt {-6}$ does not have any real number solutions, $x$ does not have any real number solutions either.
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