Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 39

Answer

{$-8, 2$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $(x+b)^{2}=a$ can be written as $x+b=\pm\sqrt a$, we obtain: Step 1: $(x+3)^{2}=25$ Step 2: $x+3=\pm \sqrt {25}$ Step 3: $x+3=\pm 5$ Step 4: $x+3=5$ or $x+3=-5$ Step 5: $x=5-3$ or $x=-5-3$ Step 6: $x=2$ or $x=-8$ The solution set is {$-8, 2$}.
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