Answer
{$7-\sqrt 6,7+\sqrt 6$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
Step 1: $(x-7)^{2}=6$
Step 2: $x-7=\pm \sqrt {6}$
Step 3: $x-7=+ \sqrt {6}$ or $x-7=- \sqrt {6}$
Step 4: $x=7+\sqrt 6$ or $x=7-\sqrt 6$
The solution set is {$7-\sqrt 6,7+\sqrt 6$}.
