Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 44


{$7-\sqrt 6,7+\sqrt 6$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(x-7)^{2}=6$ Step 2: $x-7=\pm \sqrt {6}$ Step 3: $x-7=+ \sqrt {6}$ or $x-7=- \sqrt {6}$ Step 4: $x=7+\sqrt 6$ or $x=7-\sqrt 6$ The solution set is {$7-\sqrt 6,7+\sqrt 6$}.
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