Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 40

Answer

{$-11, 1$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $(x+b)^{2}=a$ can be written as $x+b=\pm\sqrt a$, we obtain: Step 1: $(x+5)^{2}=36$ Step 2: $x+5=\pm \sqrt {36}$ Step 3: $x+5=\pm 6$ Step 4: $x+5=6$ or $x+5=-6$ Step 5: $x=6-5$ or $x=-6-5$ Step 6: $x=1$ or $x=-11$ The solution set is {$-11,1$}.
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