Answer
{$-11, 1$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $(x+b)^{2}=a$ can be written as $x+b=\pm\sqrt a$, we obtain:
Step 1: $(x+5)^{2}=36$
Step 2: $x+5=\pm \sqrt {36}$
Step 3: $x+5=\pm 6$
Step 4: $x+5=6$ or $x+5=-6$
Step 5: $x=6-5$ or $x=-6-5$
Step 6: $x=1$ or $x=-11$
The solution set is {$-11,1$}.
