Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 10

Answer

{$-4,9$}

Work Step by Step

Using the rules of factoring trinomials, we obtain: $x^{2}-5x-36=0$ $x^{2}+4x-9x-36=0$ $x(x+4)-9(x+4)=0$ $(x+4)(x-9)=0$ $(x+4)=0$ and $(x-9)=0$ $x=-4$ and $x=9$ Therefore, the solution set is {$-4,9$}.
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