Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 25

Answer

{$-\sqrt {14},\sqrt {14}$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $n^{2}=14$ Step 2: $n=\pm \sqrt {14}$ The solution set is {$-\sqrt {14},\sqrt {14}$}.
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