Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 41



Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $(x-b)^{2}=a$ can be written as $x-b=\pm\sqrt a$, we obtain: Step 1: $(3x-2)^{2}=49$ Step 2: $3x-2=\pm \sqrt {49}$ Step 3: $3x-2=\pm 7$ Step 4: $3x-2=7$ or $3x-2=-7$ Step 5: $3x=7+2$ or $3x=-7+2$ Step 6: $3x=9$ or $3x=-5$ Step 7: $x=3$ or $x=-\frac{5}{3}$ The solution set is {$-\frac{5}{3},3$}.
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