Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 18

Answer

{$-\frac{2}{3}$}

Work Step by Step

Using the rules for factoring trinomials and setting the factors equal to zero, we obtain: $9x^{2}+12x+4=0$ $9x^{2}+6x+6x+4=0$ $3x(3x+2)+2(3x+2)=0$ $(3x+2)(3x+2)=0$ $(3x+2)=0$ or $(3x+2)=0$ $x=-\frac{2}{3}$ Therefore, the solution set is {$-\frac{2}{3}$}.
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