Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 43

{$-6-\sqrt 5,-6+\sqrt 5$}

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(x+6)^{2}=5$ Step 2: $x+6=\pm \sqrt {5}$ Step 3: $x+6=+ \sqrt {5}$ or $x+6=- \sqrt {5}$ Step 4: $x=-6+\sqrt 5$ or $x=-6-\sqrt 5$ The solution set is {$-6-\sqrt 5,-6+\sqrt 5$}.