Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 43


{$-6-\sqrt 5,-6+\sqrt 5$}

Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(x+6)^{2}=5$ Step 2: $x+6=\pm \sqrt {5}$ Step 3: $x+6=+ \sqrt {5}$ or $x+6=- \sqrt {5}$ Step 4: $x=-6+\sqrt 5$ or $x=-6-\sqrt 5$ The solution set is {$-6-\sqrt 5,-6+\sqrt 5$}.
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