Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 53



Work Step by Step

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $2(7x-1)^{2}+5=37$ Step 2: $2(7x-1)^{2}=37-5$ Step 3: $2(7x-1)^{2}=32$ Step 4: $(7x-1)^{2}=16$ Step 5: $7x-1=\pm \sqrt {16}$ Step 6: $7x-1=\pm 4$ Step 7: $7x-1=4$ or $7x-1=-4$ Step 8: $7x=4+1$ or $7x=-4+1$ Step 9: $7x=5$ or $7x=-3$ Step 10: $x=\frac{5}{7}$ or $x=-\frac{3}{7}$ The solution set is {$-\frac{3}{7},\frac{5}{7}$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.