Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 7



Work Step by Step

Using the rules of factoring trinomials, we obtain: $x^{2}-9x+8=0$ $x^{2}-1x-8x+8=0$ $x(x-1)-8(x-1)=0$ $(x-1)(x-8)=0$ $(x-1)=0$ and $(x-8)=0$ $x=1$ and $x=8$ Therefore, the solution set is {$1,8$}.
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