College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 139: 76

Answer

The solution is $x=-\dfrac{b}{a}$

Work Step by Step

$a^3x^3+b^3=0\hspace{0.7cm} \color{blue}{\text{Given equation}}$ $\Rightarrow a^3x^3=-b^3$ $\Rightarrow x^3=-\dfrac{b^3}{a^3}$ $\Rightarrow x=-\bigg(\dfrac{b^3}{a^3}\bigg)^{1/3}=-\dfrac{(b^3)^{1/3}}{(a^3)^{1/3}}=-\dfrac{b}{a}$ The solution is $x=-\dfrac{b}{a}$
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