## College Algebra 7th Edition

$x=\frac{5}{4}$
$\displaystyle \sqrt{8x-1}=3$ $(\sqrt{8x-1})^{2}=3^{2}$ $8x-1=9$ $8x=9+1=10$ $x=\frac{10}{8}$ $x=\frac{5}{4}$ We need to confirm that the solution $x=\frac{5}{4}$ works in the original equation: $\sqrt{8(\frac{5}{4})-1}=\sqrt{10-1}=\sqrt{9}=3$ Which is true.