Answer
$x=0$ or $x=2$
Work Step by Step
$\sqrt[3]{4x^{2}-4x}=x$
$4x^{2}-4x=x^{3}$
$4x^{2}-4x-x^{3}=0$
$x^{3}-4x^{2}+4x=0$
$x(x^{2}-4x+4)=0$
$x(x-2)^{2}=0$
$x=0$ or $x-2=0$
$x=0$ or $x=2$
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