## College Algebra 7th Edition

$x=\sqrt[3]{3}$ or $x=-1$
$x^{6}-2x^{3}-3=0$ We factor and solve: $(x^{3}-3)(x^{3}+1)$ $x^{3}-3=0$ or $x^{3}+1=0$ $x^3=3$ or $x^3=-1$ $x=\sqrt[3]{3}$ or $x=\sqrt[3]{-1}=-1$