#### Answer

$x=7$

#### Work Step by Step

$5=\sqrt{4x-3}$
$5^{2}=(\sqrt{4x-3})^{2}$
$25=4x-3$
$25+3=4x$
$4x=28$
$x=28/4=7$
We need to confirm that the solution $x=7$ works in the original equation:
$\sqrt{4(7)-3}=\sqrt{28-3}=\sqrt{25}=5$
Which is true.

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=7$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.