#### Answer

$x=3$ or $x=-1$

#### Work Step by Step

$x^{6}-26x^{3}-27=0$
We factor and solve:
$(x^{3}-27)(x^{3}+1)=0$
$x^{3}-27=0$ or $x^{3}+1=0$
$x^3=27$ or $x^3=-1$
$x=\sqrt[3]{27}=3$ or $x=\sqrt[3]{-1}=-1$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=3$ or $x=-1$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.