Answer
$x=3$ or $x=-1$
Work Step by Step
$x^{6}-26x^{3}-27=0$
We factor and solve:
$(x^{3}-27)(x^{3}+1)=0$
$x^{3}-27=0$ or $x^{3}+1=0$
$x^3=27$ or $x^3=-1$
$x=\sqrt[3]{27}=3$ or $x=\sqrt[3]{-1}=-1$
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