#### Answer

$x=-\frac{1}{2}$

#### Work Step by Step

$\displaystyle \frac{1}{x^{3}}+\frac{4}{x^{2}}+\frac{4}{x}=0$
We multiply through by $x^3$:
$1+4x+4x^{2}=0$
Now we factor and solve:
$(1+2x)^{2}=0$
$1+2x=0$
$2x=-1$
$x=-\frac{1}{2}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=-\frac{1}{2}$

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