Answer
$x=\pm\sqrt{a}$ or $x=\pm2\sqrt{a}$
Work Step by Step
$x^{4}-5ax^{2}+4a^{2}=0$
$(a-x^{2})(4a-x^{2})=0$
$a-x^2=0$ or $4a-x^2=0$
$x=\pm\sqrt{a}$ or $x=\pm2\sqrt{a}$
(We can take the square root of $a$ because it is positive.)
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 139: 75
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