College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 64

Answer

$x=3$

Work Step by Step

$x^{1/2}-x^{-1/2}-6x^{-3/2}=0$ $x^{-3/2}(x^{2}-x-6)=0$ $x^{-3/2}(x+2)(x-3)=0$ $x^{-3/2}=0$ or $x+2=0$ or $x-3=0$ $\frac{1}{x^{3/2}}=0$ or $x=-2$ or $x=3$ The left equation has no solution. The middle solution will not work in the original equation (we can not take the square root of a negative number). Thus the only solution is $x=3$
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