#### Answer

$x=0$ or $x=-7$

#### Work Step by Step

$(x+5)^{2}-3(x+5)-10=0$
$[(x+5)-5][(x+5)+2]=0$
$x(x+7)=0$
$x=0$ or $x+7=0$
$x=0$ or $x=-7$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=0$ or $x=-7$

$(x+5)^{2}-3(x+5)-10=0$
$[(x+5)-5][(x+5)+2]=0$
$x(x+7)=0$
$x=0$ or $x+7=0$
$x=0$ or $x=-7$

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