Answer
(2, 3) or ($-\frac{3}{2}$, -4)
Work Step by Step
2x - y = 1 can be written as y = 2x - 1. Plug this into xy = 6
x (2x - 1) = 6
$2x^{2} - x - 6 = 0$
Factor
(x - 2)(2x + 3) = 0
x - 2 = 0 or 2x + 3 = 0
x = 2 or $-\frac{3}{2}$
Plug x-values into y = 2x - 1
For x = 2: y = 2(2) - 1 = 3
For x = $-\frac{3}{2}$: y = 2($-\frac{3}{2}$) - 1 = -4
(2, 3) or ($-\frac{3}{2}$, -4)
